64=-3x+4(3x-2)

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Solution for 64=-3x+4(3x-2) equation: 



64=-3x+4(3x-2)

We move all terms to the left:

64-(-3x+4(3x-2))=0



We calculate terms in parentheses: -(-3x+4(3x-2)), so:

-3x+4(3x-2)

We multiply parentheses

-3x+12x-8

We add all the numbers together, and all the variables

9x-8

Back to the equation:

-(9x-8)



We get rid of parentheses

-9x+8+64=0

We add all the numbers together, and all the variables

-9x+72=0

We move all terms containing x to the left, all other terms to the right

-9x=-72

x=-72/-9

x=+8

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