64=1/2(12.6)h

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Solution for 64=1/2(12.6)h equation: 



64=1/2(12.6)h

We move all terms to the left:

64-(1/2(12.6)h)=0



Domain of the equation: 2(12.6)h)!=0

h∈R



We multiply all the terms by the denominator


-(1+64*2(12.6)h)=0



We calculate terms in parentheses: -(1+64*2(12.6)h), so:

1+64*2(12.6)h

determiningTheFunctionDomain
64*2(12.6)h+1

Wy multiply elements

128h(1+1

Back to the equation:

-(128h(1+1)



We add all the numbers together, and all the variables

-(128h2=0

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