64=1/2(x+1)(3x-7)

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Solution for 64=1/2(x+1)(3x-7) equation: 



64=1/2(x+1)(3x-7)

We move all terms to the left:

64-(1/2(x+1)(3x-7))=0



Domain of the equation: 2(x+1)(3x-7))!=0

x∈R



We multiply parentheses ..

-(1/2(+3x^2-7x+3x-7))+64=0

We multiply all the terms by the denominator


-(1+64*2(+3x^2-7x+3x-7))=0



We calculate terms in parentheses: -(1+64*2(+3x^2-7x+3x-7)), so:

1+64*2(+3x^2-7x+3x-7)

determiningTheFunctionDomain
64*2(+3x^2-7x+3x-7)+1

Wy multiply elements

128x(++1

We use the square of the difference formula

128x(+1

Back to the equation:

-(128x(+1)



We add all the numbers together, and all the variables

-(128x1=0

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