64=10+2*(x+2)+3x+(10-x)

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Solution for 64=10+2*(x+2)+3x+(10-x) equation: 



64=10+2(x+2)+3x+(10-x)

We move all terms to the left:

64-(10+2(x+2)+3x+(10-x))=0

We add all the numbers together, and all the variables

-(10+2(x+2)+3x+(-1x+10))+64=0



We calculate terms in parentheses: -(10+2(x+2)+3x+(-1x+10)), so:

10+2(x+2)+3x+(-1x+10)

determiningTheFunctionDomain
2(x+2)+3x+(-1x+10)+10

We add all the numbers together, and all the variables

3x+2(x+2)+(-1x+10)+10

We multiply parentheses

3x+2x+(-1x+10)+4+10

We get rid of parentheses

3x+2x-1x+10+4+10

We add all the numbers together, and all the variables

4x+24

Back to the equation:

-(4x+24)



We get rid of parentheses

-4x-24+64=0

We add all the numbers together, and all the variables

-4x+40=0

We move all terms containing x to the left, all other terms to the right

-4x=-40

x=-40/-4

x=+10

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