64=2(12)+2(x+6)

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Solution for 64=2(12)+2(x+6) equation: 



64=2(12)+2(x+6)

We move all terms to the left:

64-(2(12)+2(x+6))=0



We calculate terms in parentheses: -(212+2(x+6)), so:

212+2(x+6)

determiningTheFunctionDomain
2(x+6)+212

We multiply parentheses

2x+12+212

We add all the numbers together, and all the variables

2x+224

Back to the equation:

-(2x+224)



We get rid of parentheses

-2x-224+64=0

We add all the numbers together, and all the variables

-2x-160=0

We move all terms containing x to the left, all other terms to the right

-2x=160

x=160/-2

x=-80

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