64=4(1+3k)

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Solution for 64=4(1+3k) equation: 



64=4(1+3k)

We move all terms to the left:

64-(4(1+3k))=0

We add all the numbers together, and all the variables

-(4(3k+1))+64=0



We calculate terms in parentheses: -(4(3k+1)), so:

4(3k+1)

We multiply parentheses

12k+4

Back to the equation:

-(12k+4)



We get rid of parentheses

-12k-4+64=0

We add all the numbers together, and all the variables

-12k+60=0

We move all terms containing k to the left, all other terms to the right

-12k=-60

k=-60/-12

k=+5

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