64=4(1-3b)

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Solution for 64=4(1-3b) equation: 



64=4(1-3b)

We move all terms to the left:

64-(4(1-3b))=0

We add all the numbers together, and all the variables

-(4(-3b+1))+64=0



We calculate terms in parentheses: -(4(-3b+1)), so:

4(-3b+1)

We multiply parentheses

-12b+4

Back to the equation:

-(-12b+4)



We get rid of parentheses

12b-4+64=0

We add all the numbers together, and all the variables

12b+60=0

We move all terms containing b to the left, all other terms to the right

12b=-60

b=-60/12

b=-5

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