64=4(u+13)

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Solution for 64=4(u+13) equation: 



64=4(u+13)

We move all terms to the left:

64-(4(u+13))=0



We calculate terms in parentheses: -(4(u+13)), so:

4(u+13)

We multiply parentheses

4u+52

Back to the equation:

-(4u+52)



We get rid of parentheses

-4u-52+64=0

We add all the numbers together, and all the variables

-4u+12=0

We move all terms containing u to the left, all other terms to the right

-4u=-12

u=-12/-4

u=+3

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