64=4x+4(3x-4)

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Solution for 64=4x+4(3x-4) equation: 



64=4x+4(3x-4)

We move all terms to the left:

64-(4x+4(3x-4))=0



We calculate terms in parentheses: -(4x+4(3x-4)), so:

4x+4(3x-4)

We multiply parentheses

4x+12x-16

We add all the numbers together, and all the variables

16x-16

Back to the equation:

-(16x-16)



We get rid of parentheses

-16x+16+64=0

We add all the numbers together, and all the variables

-16x+80=0

We move all terms containing x to the left, all other terms to the right

-16x=-80

x=-80/-16

x=+5

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