64=y+(y+3)+(2y-11)

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Solution for 64=y+(y+3)+(2y-11) equation: 


Simplifying
64 = y + (y + 3) + (2y + -11)

Reorder the terms:
64 = y + (3 + y) + (2y + -11)

Remove parenthesis around (3 + y)
64 = y + 3 + y + (2y + -11)

Reorder the terms:
64 = y + 3 + y + (-11 + 2y)

Remove parenthesis around (-11 + 2y)
64 = y + 3 + y + -11 + 2y

Reorder the terms:
64 = 3 + -11 + y + y + 2y

Combine like terms: 3 + -11 = -8
64 = -8 + y + y + 2y

Combine like terms: y + y = 2y
64 = -8 + 2y + 2y

Combine like terms: 2y + 2y = 4y
64 = -8 + 4y

Solving
64 = -8 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
64 + -4y = -8 + 4y + -4y

Combine like terms: 4y + -4y = 0
64 + -4y = -8 + 0
64 + -4y = -8

Add '-64' to each side of the equation.
64 + -64 + -4y = -8 + -64

Combine like terms: 64 + -64 = 0
0 + -4y = -8 + -64
-4y = -8 + -64

Combine like terms: -8 + -64 = -72
-4y = -72

Divide each side by '-4'.
y = 18

Simplifying
y = 18

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