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64v^2-2=2
We move all terms to the left:
64v^2-2-(2)=0
We add all the numbers together, and all the variables
64v^2-4=0
a = 64; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·64·(-4)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*64}=\frac{-32}{128} =-1/4 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*64}=\frac{32}{128} =1/4 $
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