64w2-48w+9=0

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Solution for 64w2-48w+9=0 equation:



64w^2-48w+9=0
a = 64; b = -48; c = +9;
Δ = b2-4ac
Δ = -482-4·64·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{48}{128}=3/8$

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