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64x-2(3x-1)=3(1+83x)+12
We move all terms to the left:
64x-2(3x-1)-(3(1+83x)+12)=0
We add all the numbers together, and all the variables
64x-2(3x-1)-(3(83x+1)+12)=0
We multiply parentheses
64x-6x-(3(83x+1)+12)+2=0
We calculate terms in parentheses: -(3(83x+1)+12), so:We add all the numbers together, and all the variables
3(83x+1)+12
We multiply parentheses
249x+3+12
We add all the numbers together, and all the variables
249x+15
Back to the equation:
-(249x+15)
58x-(249x+15)+2=0
We get rid of parentheses
58x-249x-15+2=0
We add all the numbers together, and all the variables
-191x-13=0
We move all terms containing x to the left, all other terms to the right
-191x=13
x=13/-191
x=-13/191
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