64x2+128x+20=0

Solution for 64x2+128x+20=0 equation:

64x^2+128x+20=0

a = 64; b = 128; c = +20;
Δ = b2-4ac
Δ = 1282-4·64·20
Δ = 11264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11264}=\sqrt{1024*11}=\sqrt{1024}*\sqrt{11}=32\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(128)-32\sqrt{11}}{2*64}=\frac{-128-32\sqrt{11}}{128}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(128)+32\sqrt{11}}{2*64}=\frac{-128+32\sqrt{11}}{128}
$