64x2+129x+64=0

Solution for 64x2+129x+64=0 equation:

64x^2+129x+64=0

a = 64; b = 129; c = +64;
Δ = b2-4ac
Δ = 1292-4·64·64
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(129)-\sqrt{257}}{2*64}=\frac{-129-\sqrt{257}}{128}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(129)+\sqrt{257}}{2*64}=\frac{-129+\sqrt{257}}{128}
$