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64x^2-116x+30=0
a = 64; b = -116; c = +30;
Δ = b2-4ac
Δ = -1162-4·64·30
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-116)-76}{2*64}=\frac{40}{128} =5/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-116)+76}{2*64}=\frac{192}{128} =1+1/2 $
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