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64x^2-529=0
a = 64; b = 0; c = -529;
Δ = b2-4ac
Δ = 02-4·64·(-529)
Δ = 135424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{135424}=368$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-368}{2*64}=\frac{-368}{128} =-2+7/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+368}{2*64}=\frac{368}{128} =2+7/8 $
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