64x2-80x+25=0

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Solution for 64x2-80x+25=0 equation: 



64x^2-80x+25=0

a = 64; b = -80; c = +25;
Δ = b2-4ac
Δ = -802-4·64·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{80}{128}=5/8$

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