If it's not what You are looking for type in the equation solver your own equation and let us solve it.
64x^2-9=0
a = 64; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·64·(-9)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*64}=\frac{-48}{128} =-3/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*64}=\frac{48}{128} =3/8 $
| x/3=1^1/2 | | 4=x+26/5 | | x/3=11/2 | | 1/x=0.16 | | 5x(4x2-12x+9)=0 | | -16=-9+n | | 1.2(h+2)=2h-1 | | -6=h-3 | | 2(4x-3)=5(2x-5 | | X²-20x+100=0 | | 5(r-4)-4(r-1)=2(r+3) | | Y=3+2x-x^2 | | 2x+9=-14 | | 4x2+30x+14=0 | | -15=9+3u | | 18x3-24x2+8x=0 | | w/6+12=8 | | 2x+150+x×1/5=1350 | | 9(4a+8)=12(6+3a) | | 66x=20 | | x+2/5-x-1/2=3x-9/2 | | 3(2x+1)-4(2-x)=3x | | 6+2x^2-9x=0 | | 2x²9x=0 | | 6+2x²9x=0 | | 18x2-24x2+8x=0 | | 6+5y=27 | | 5*x+1=5 | | x+1*5=5 | | 5*(x+1)=5 | | 10x2-3x-18=0 | | 8x-8x-4=2 |