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64y^2+66y+2=0
a = 64; b = 66; c = +2;
Δ = b2-4ac
Δ = 662-4·64·2
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-62}{2*64}=\frac{-128}{128} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+62}{2*64}=\frac{-4}{128} =-1/32 $
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