65(4x+1)=(7x+3)

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Solution for 65(4x+1)=(7x+3) equation: 



65(4x+1)=(7x+3)

We move all terms to the left:

65(4x+1)-((7x+3))=0

We multiply parentheses

260x-((7x+3))+65=0



We calculate terms in parentheses: -((7x+3)), so:

(7x+3)

We get rid of parentheses

7x+3

Back to the equation:

-(7x+3)



We get rid of parentheses

260x-7x-3+65=0

We add all the numbers together, and all the variables

253x+62=0

We move all terms containing x to the left, all other terms to the right

253x=-62

x=-62/253

x=-62/253

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