65+(3x-5)+(1/4(8x-80))=180

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Solution for 65+(3x-5)+(1/4(8x-80))=180 equation: 



65+(3x-5)+(1/4(8x-80))=180

We move all terms to the left:

65+(3x-5)+(1/4(8x-80))-(180)=0



Domain of the equation: 4(8x-80))!=0

x∈R



We add all the numbers together, and all the variables

(3x-5)+(1/4(8x-80))-115=0

We get rid of parentheses

3x+(1/4(8x-80))-5-115=0

We multiply all the terms by the denominator


3x*4(8x-80))+(1-5*4(8x-80))-115*4(8x-80))=0

We add all the numbers together, and all the variables

3x*4(8x-80))+(1-5*4(8x-80))-115*4(8x=0

Wy multiply elements

12x^2(8-80x^2(8=0

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