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65+z=34z(3z*5-3)(-5)
We move all terms to the left:
65+z-(34z(3z*5-3)(-5))=0
We multiply parentheses ..
z-(34z(-75z+15))+65=0
We calculate terms in parentheses: -(34z(-75z+15)), so:We get rid of parentheses
34z(-75z+15)
We multiply parentheses
-2550z^2+510z
Back to the equation:
-(-2550z^2+510z)
2550z^2-510z+z+65=0
We add all the numbers together, and all the variables
2550z^2-509z+65=0
a = 2550; b = -509; c = +65;
Δ = b2-4ac
Δ = -5092-4·2550·65
Δ = -403919
Delta is less than zero, so there is no solution for the equation
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