65-(3x+4)=3(x+4)+x

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Solution for 65-(3x+4)=3(x+4)+x equation: 



65-(3x+4)=3(x+4)+x

We move all terms to the left:

65-(3x+4)-(3(x+4)+x)=0

We get rid of parentheses

-3x-(3(x+4)+x)-4+65=0



We calculate terms in parentheses: -(3(x+4)+x), so:

3(x+4)+x

We add all the numbers together, and all the variables

x+3(x+4)

We multiply parentheses

x+3x+12

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

-3x-(4x+12)+61=0

We get rid of parentheses

-3x-4x-12+61=0

We add all the numbers together, and all the variables

-7x+49=0

We move all terms containing x to the left, all other terms to the right

-7x=-49

x=-49/-7

x=+7

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