65.36+21.74y(0.004856-y)=100-14.49y(1+y)

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Solution for 65.36+21.74y(0.004856-y)=100-14.49y(1+y) equation: 



65.36+21.74y(0.004856-y)=100-14.49y(1+y)

We move all terms to the left:

65.36+21.74y(0.004856-y)-(100-14.49y(1+y))=0

We add all the numbers together, and all the variables

21.74y(-1y+0.004856)-(100-14.49y(y+1))+65.36=0

We multiply parentheses

-21y^2+0.101976y-(100-14.49y(y+1))+65.36=0



We calculate terms in parentheses: -(100-14.49y(y+1)), so:

100-14.49y(y+1)

determiningTheFunctionDomain
-14.49y(y+1)+100

We multiply parentheses

-14y^2-14y+100

Back to the equation:

-(-14y^2-14y+100)



We get rid of parentheses

-21y^2+14y^2+14y+0.101976y-100+65.36=0

We add all the numbers together, and all the variables

-7y^2+14.101976y-34.64=0

a = -7; b = 14.101976; c = -34.64;
Δ = b2-4ac
Δ = 14.1019762-4·(-7)·(-34.64)
Δ = -771.05427289542
Delta is less than zero, so there is no solution for the equation

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