65=(2x+7)+(8x-2)

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Solution for 65=(2x+7)+(8x-2) equation: 



65=(2x+7)+(8x-2)

We move all terms to the left:

65-((2x+7)+(8x-2))=0



We calculate terms in parentheses: -((2x+7)+(8x-2)), so:

(2x+7)+(8x-2)

We get rid of parentheses

2x+8x+7-2

We add all the numbers together, and all the variables

10x+5

Back to the equation:

-(10x+5)



We get rid of parentheses

-10x-5+65=0

We add all the numbers together, and all the variables

-10x+60=0

We move all terms containing x to the left, all other terms to the right

-10x=-60

x=-60/-10

x=+6

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