65=(3/5(c))-7

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Solution for 65=(3/5(c))-7 equation: 



65=(3/5(c))-7

We move all terms to the left:

65-((3/5(c))-7)=0



Domain of the equation: 5c)-7)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

-((+3/5c)-7)+65=0

We multiply all the terms by the denominator


-((+3+65*5c)-7)=0



We calculate terms in parentheses: -((+3+65*5c)-7), so:

(+3+65*5c)-7

We add all the numbers together, and all the variables

(65*5c+3)-7

We get rid of parentheses

65*5c+3-7

We add all the numbers together, and all the variables

65*5c-4

Wy multiply elements

325c-4

Back to the equation:

-(325c-4)



We get rid of parentheses

-325c+4=0

We move all terms containing c to the left, all other terms to the right

-325c=-4

c=-4/-325

c=4/325

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