65=(3a-2)*a

Solution for 65=(3a-2)*a equation:

65=(3a-2)*a

We move all terms to the left:

65-((3a-2)*a)=0


We calculate terms in parentheses: -((3a-2)*a), so:

(3a-2)*a

We multiply parentheses

3a^2-2a

Back to the equation:

-(3a^2-2a)


We get rid of parentheses

-3a^2+2a+65=0

a = -3; b = 2; c = +65;
Δ = b2-4ac
Δ = 22-4·(-3)·65
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-28}{2*-3}=\frac{-30}{-6}
=+5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+28}{2*-3}=\frac{26}{-6}
=-4+1/3
$