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65=1/5(w-50)
We move all terms to the left:
65-(1/5(w-50))=0
Domain of the equation: 5(w-50))!=0We multiply all the terms by the denominator
w∈R
-(1+65*5(w-50))=0
We calculate terms in parentheses: -(1+65*5(w-50)), so:
1+65*5(w-50)
determiningTheFunctionDomain 65*5(w-50)+1
Wy multiply elements
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Back to the equation:
-(325w(w+1)
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| 5c2+12c+6=0 | | -3(3a+4)+15a=6 | | -2(1/4)=r-(4/5) | | -7x-14=3(x+2) | | 17k=204 | | -3.2f+0.18+1.8f=-15.57-2.9f | | 14x=183 | | 4/3x-2=6/2x-1 | | -32=p-20 | | 29x+40+3x=33 | | x=2560(.08) | | 9.98-14.2k=-10.82-19.4k | | 2x-4(x-3)=-8+3x-20 | | 3v+-9v=-70 | | 2(v+6)=-7v-33 | | 2x-1+6x=-7x+4 | | 3x-1/4=10 | | 7+3w=4w-12 | | 2+5(4x-7)=37+6x | | 2(v+6)=7v-33 | | 12+9h=10h | | 2=4+r | | 25t=375 | | 2x+4x-3=x+22 | | -35y=315 | | x/8+3=-46 | | 9=-2+b | | 1x+20+4=160 | | -3-2x-7=10 | | 6x=183 | | 2x-10=x-33 | | 8.4*x=69.3 |