65=20i+5(1-i)

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Solution for 65=20i+5(1-i) equation:



65=20i+5(1-i)
We move all terms to the left:
65-(20i+5(1-i))=0
We add all the numbers together, and all the variables
-(20i+5(-1i+1))+65=0
We calculate terms in parentheses: -(20i+5(-1i+1)), so:
20i+5(-1i+1)
We multiply parentheses
20i-5i+5
We add all the numbers together, and all the variables
15i+5
Back to the equation:
-(15i+5)
We get rid of parentheses
-15i-5+65=0
We add all the numbers together, and all the variables
-15i+60=0
We move all terms containing i to the left, all other terms to the right
-15i=-60
i=-60/-15
i=+4

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