65=20j+5(1-j)

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Solution for 65=20j+5(1-j) equation: 



65=20j+5(1-j)

We move all terms to the left:

65-(20j+5(1-j))=0

We add all the numbers together, and all the variables

-(20j+5(-1j+1))+65=0



We calculate terms in parentheses: -(20j+5(-1j+1)), so:

20j+5(-1j+1)

We multiply parentheses

20j-5j+5

We add all the numbers together, and all the variables

15j+5

Back to the equation:

-(15j+5)



We get rid of parentheses

-15j-5+65=0

We add all the numbers together, and all the variables

-15j+60=0

We move all terms containing j to the left, all other terms to the right

-15j=-60

j=-60/-15

j=+4

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