65=3/4z+7

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Solution for 65=3/4z+7 equation: 



65=3/4z+7

We move all terms to the left:

65-(3/4z+7)=0



Domain of the equation: 4z+7)!=0

z∈R



We get rid of parentheses

-3/4z-7+65=0

We multiply all the terms by the denominator


-7*4z+65*4z-3=0

Wy multiply elements

-28z+260z-3=0

We add all the numbers together, and all the variables

232z-3=0

We move all terms containing z to the left, all other terms to the right

232z=3

z=3/232

z=3/232

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