65c+74c(96c+c-c)=79

Solution for 65c+74c(96c+c-c)=79 equation:

65c+74c(96c+c-c)=79

We move all terms to the left:

65c+74c(96c+c-c)-(79)=0

We add all the numbers together, and all the variables

65c+74c(+96c)-79=0

We multiply parentheses

7104c^2+65c-79=0

a = 7104; b = 65; c = -79;
Δ = b2-4ac
Δ = 652-4·7104·(-79)
Δ = 2249089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-\sqrt{2249089}}{2*7104}=\frac{-65-\sqrt{2249089}}{14208}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+\sqrt{2249089}}{2*7104}=\frac{-65+\sqrt{2249089}}{14208}
$