66-2(z+1)=6z+4z+4

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Solution for 66-2(z+1)=6z+4z+4 equation: 



66-2(z+1)=6z+4z+4

We move all terms to the left:

66-2(z+1)-(6z+4z+4)=0

We add all the numbers together, and all the variables

-2(z+1)-(10z+4)+66=0

We multiply parentheses

-2z-(10z+4)-2+66=0

We get rid of parentheses

-2z-10z-4-2+66=0

We add all the numbers together, and all the variables

-12z+60=0

We move all terms containing z to the left, all other terms to the right

-12z=-60

z=-60/-12

z=+5

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