66-6x+15+49x+3=40x-15

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Solution for 66-6x+15+49x+3=40x-15 equation: 



66-6x+15+49x+3=40x-15

We move all terms to the left:

66-6x+15+49x+3-(40x-15)=0

We add all the numbers together, and all the variables

43x-(40x-15)+84=0

We get rid of parentheses

43x-40x+15+84=0

We add all the numbers together, and all the variables

3x+99=0

We move all terms containing x to the left, all other terms to the right

3x=-99

x=-99/3

x=-33

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