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660x(3/10)=30
We move all terms to the left:
660x(3/10)-(30)=0
We add all the numbers together, and all the variables
660x(+3/10)-30=0
We multiply parentheses
1980x^2-30=0
a = 1980; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·1980·(-30)
Δ = 237600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{237600}=\sqrt{3600*66}=\sqrt{3600}*\sqrt{66}=60\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{66}}{2*1980}=\frac{0-60\sqrt{66}}{3960} =-\frac{60\sqrt{66}}{3960} =-\frac{\sqrt{66}}{66} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{66}}{2*1980}=\frac{0+60\sqrt{66}}{3960} =\frac{60\sqrt{66}}{3960} =\frac{\sqrt{66}}{66} $
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