66=(10+b2)6

Solution for 66=(10+b2)6 equation:

66=(10+b2)6

We move all terms to the left:

66-((10+b2)6)=0

We add all the numbers together, and all the variables

-((+b^2+10)6)+66=0


We calculate terms in parentheses: -((+b^2+10)6), so:

(+b^2+10)6

We multiply parentheses

6b^2+60

Back to the equation:

-(6b^2+60)


We get rid of parentheses

-6b^2-60+66=0

We add all the numbers together, and all the variables

-6b^2+6=0

a = -6; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·(-6)·6
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*-6}=\frac{-12}{-12}
=1
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*-6}=\frac{12}{-12}
=-1
$