66=-2(1-x)+5(2x+4)

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Solution for 66=-2(1-x)+5(2x+4) equation: 



66=-2(1-x)+5(2x+4)

We move all terms to the left:

66-(-2(1-x)+5(2x+4))=0

We add all the numbers together, and all the variables

-(-2(-1x+1)+5(2x+4))+66=0



We calculate terms in parentheses: -(-2(-1x+1)+5(2x+4)), so:

-2(-1x+1)+5(2x+4)

We multiply parentheses

2x+10x-2+20

We add all the numbers together, and all the variables

12x+18

Back to the equation:

-(12x+18)



We get rid of parentheses

-12x-18+66=0

We add all the numbers together, and all the variables

-12x+48=0

We move all terms containing x to the left, all other terms to the right

-12x=-48

x=-48/-12

x=+4

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