66=2(x)+2(2x-3)

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Solution for 66=2(x)+2(2x-3) equation: 



66=2(x)+2(2x-3)

We move all terms to the left:

66-(2(x)+2(2x-3))=0



We calculate terms in parentheses: -(2x+2(2x-3)), so:

2x+2(2x-3)

We multiply parentheses

2x+4x-6

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

-6x+6+66=0

We add all the numbers together, and all the variables

-6x+72=0

We move all terms containing x to the left, all other terms to the right

-6x=-72

x=-72/-6

x=+12

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