66=2z+12+11+3z-1+z+2

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Solution for 66=2z+12+11+3z-1+z+2 equation: 



66=2z+12+11+3z-1+z+2

We move all terms to the left:

66-(2z+12+11+3z-1+z+2)=0

We add all the numbers together, and all the variables

-(6z+24)+66=0

We get rid of parentheses

-6z-24+66=0

We add all the numbers together, and all the variables

-6z+42=0

We move all terms containing z to the left, all other terms to the right

-6z=-42

z=-42/-6

z=+7

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