66=2z+12+11+3z-1+z+2

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Solution for 66=2z+12+11+3z-1+z+2 equation:



66=2z+12+11+3z-1+z+2
We move all terms to the left:
66-(2z+12+11+3z-1+z+2)=0
We add all the numbers together, and all the variables
-(6z+24)+66=0
We get rid of parentheses
-6z-24+66=0
We add all the numbers together, and all the variables
-6z+42=0
We move all terms containing z to the left, all other terms to the right
-6z=-42
z=-42/-6
z=+7

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