66=4(1-2x)=7(7x+3)

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Solution for 66=4(1-2x)=7(7x+3) equation: 



66=4(1-2x)=7(7x+3)

We move all terms to the left:

66-(4(1-2x))=0

We add all the numbers together, and all the variables

-(4(-2x+1))+66=0



We calculate terms in parentheses: -(4(-2x+1)), so:

4(-2x+1)

We multiply parentheses

-8x+4

Back to the equation:

-(-8x+4)



We get rid of parentheses

8x-4+66=0

We add all the numbers together, and all the variables

8x+62=0

We move all terms containing x to the left, all other terms to the right

8x=-62

x=-62/8

x=-7+3/4

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