66=4y+3(2y+2)+2y

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Solution for 66=4y+3(2y+2)+2y equation: 



66=4y+3(2y+2)+2y

We move all terms to the left:

66-(4y+3(2y+2)+2y)=0



We calculate terms in parentheses: -(4y+3(2y+2)+2y), so:

4y+3(2y+2)+2y

We add all the numbers together, and all the variables

6y+3(2y+2)

We multiply parentheses

6y+6y+6

We add all the numbers together, and all the variables

12y+6

Back to the equation:

-(12y+6)



We get rid of parentheses

-12y-6+66=0

We add all the numbers together, and all the variables

-12y+60=0

We move all terms containing y to the left, all other terms to the right

-12y=-60

y=-60/-12

y=+5

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