675x2+80x=2310

Solution for 675x2+80x=2310 equation:

675x^2+80x=2310

We move all terms to the left:

675x^2+80x-(2310)=0

a = 675; b = 80; c = -2310;
Δ = b2-4ac
Δ = 802-4·675·(-2310)
Δ = 6243400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6243400}=\sqrt{100*62434}=\sqrt{100}*\sqrt{62434}=10\sqrt{62434}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-10\sqrt{62434}}{2*675}=\frac{-80-10\sqrt{62434}}{1350}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+10\sqrt{62434}}{2*675}=\frac{-80+10\sqrt{62434}}{1350}
$