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67x+22x^2-35=0
a = 22; b = 67; c = -35;
Δ = b2-4ac
Δ = 672-4·22·(-35)
Δ = 7569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7569}=87$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-87}{2*22}=\frac{-154}{44} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+87}{2*22}=\frac{20}{44} =5/11 $
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