68(3x+1)=12

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Solution for 68(3x+1)=12 equation: 



68(3x+1)=12

We move all terms to the left:

68(3x+1)-(12)=0

We multiply parentheses

204x+68-12=0

We add all the numbers together, and all the variables

204x+56=0

We move all terms containing x to the left, all other terms to the right

204x=-56

x=-56/204

x=-14/51

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