68+(4x-2)+30+112=180

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Solution for 68+(4x-2)+30+112=180 equation: 



68+(4x-2)+30+112=180

We move all terms to the left:

68+(4x-2)+30+112-(180)=0

We add all the numbers together, and all the variables

(4x-2)+30=0

We get rid of parentheses

4x-2+30=0

We add all the numbers together, and all the variables

4x+28=0

We move all terms containing x to the left, all other terms to the right

4x=-28

x=-28/4

x=-7

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