68+5/4b=128

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Solution for 68+5/4b=128 equation: 



68+5/4b=128

We move all terms to the left:

68+5/4b-(128)=0



Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R



We add all the numbers together, and all the variables

5/4b-60=0

We multiply all the terms by the denominator


-60*4b+5=0

Wy multiply elements

-240b+5=0

We move all terms containing b to the left, all other terms to the right

-240b=-5

b=-5/-240

b=1/48

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