68-4x=3(4+x)

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Solution for 68-4x=3(4+x) equation: 



68-4x=3(4+x)

We move all terms to the left:

68-4x-(3(4+x))=0

We add all the numbers together, and all the variables

-4x-(3(x+4))+68=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

-4x-3x-12+68=0

We add all the numbers together, and all the variables

-7x+56=0

We move all terms containing x to the left, all other terms to the right

-7x=-56

x=-56/-7

x=+8

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