68-x=4(x+12)

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Solution for 68-x=4(x+12) equation: 



68-x=4(x+12)

We move all terms to the left:

68-x-(4(x+12))=0

We add all the numbers together, and all the variables

-1x-(4(x+12))+68=0



We calculate terms in parentheses: -(4(x+12)), so:

4(x+12)

We multiply parentheses

4x+48

Back to the equation:

-(4x+48)



We get rid of parentheses

-1x-4x-48+68=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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