68.49+19.61y(0.005436-y)=100-13.70y(1+y)

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Solution for 68.49+19.61y(0.005436-y)=100-13.70y(1+y) equation: 



68.49+19.61y(0.005436-y)=100-13.70y(1+y)

We move all terms to the left:

68.49+19.61y(0.005436-y)-(100-13.70y(1+y))=0

We add all the numbers together, and all the variables

19.61y(-1y+0.005436)-(100-13.70y(y+1))+68.49=0

We multiply parentheses

-19y^2+0.103284y-(100-13.70y(y+1))+68.49=0



We calculate terms in parentheses: -(100-13.70y(y+1)), so:

100-13.70y(y+1)

determiningTheFunctionDomain
-13.70y(y+1)+100

We multiply parentheses

-13y^2-13y+100

Back to the equation:

-(-13y^2-13y+100)



We get rid of parentheses

-19y^2+13y^2+13y+0.103284y-100+68.49=0

We add all the numbers together, and all the variables

-6y^2+13.103284y-31.51=0

a = -6; b = 13.103284; c = -31.51;
Δ = b2-4ac
Δ = 13.1032842-4·(-6)·(-31.51)
Δ = -584.54394841534
Delta is less than zero, so there is no solution for the equation

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